FizzBuzz HackerRank Challenge

Solve the fizzbuzz hackerrank challenge question:

Given a number n, for each integer i in the range from 1 to n inclusive, print out one value per line as follows:

• if i is a multiple of both 3 and 5, print FizzBuzz
• if i is a multiple of 3(but not 5), print Fizz
• if i is a multiple of 5(but not 3), print Buzz
• if i is not a multiple of 3 or 5, print the value of i

Java Solution

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.function.*;
import java.util.regex.*;
import java.util.stream.*;
import static java.util.stream.Collectors.joining;
import static java.util.stream.Collectors.toList;



class Result {

    /*
     * Complete the 'fizzBuzz' function below.
     *
     * The function accepts INTEGER n as parameter.
     */
    public static void fizzBuzz(int n) {
        for(int i=1; i<=n; i++){
            if(i%3 == 0 && i%5 == 0){
                System.out.println("FizzBuzz");
            }else if(i%3 == 0){
                System.out.println("Fizz");
            }else if(i%5 == 0){
                System.out.println("Buzz");
            }else{
                System.out.println(i);
            }
        }
    }

}

public class Solution {
    public static void main(String[] args) throws IOException {
        BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));

        int n = Integer.parseInt(bufferedReader.readLine().trim());

        Result.fizzBuzz(n);

        bufferedReader.close();
    }
}

JavaScript Fizzbuzz Solution

'use strict';

process.stdin.resume();
process.stdin.setEncoding('utf-8');

let inputString = '';
let currentLine = 0;

process.stdin.on('data', function(inputStdin) {
    inputString += inputStdin;
});

process.stdin.on('end', function() {
    inputString = inputString.split('\n');

    main();
});

function readLine() {
    return inputString[currentLine++];
}



/*
 * Complete the 'fizzBuzz' function below.
 *
 * The function accepts INTEGER n as parameter.
 */
function fizzBuzz(n) {
    // Write your code here
    for(let i=1; i<=n; i++){
            if(i%3 == 0 && i%5 == 0){
                console.log("FizzBuzz");
            }else if(i%3 == 0){
                console.log("Fizz");
            }else if(i%5 == 0){
                console.log("Buzz");
            }else{
                console.log(i);
            }
        }

}

function main() {
    const n = parseInt(readLine().trim(), 10);

    fizzBuzz(n);
}

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Input(stdin):

15

Output (stdout):

1
2
Fizz
4
Buzz
Fizz
7
8
Fizz
Buzz
11
Fizz
13
14
FizzBuzz

This is how you solve the fizzbuzz hackerrank challenge in both Java and JavaScript.

HackerRank is a platform that offers online coding challenges to test and improve programming skills.

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